Hive – Timezone problem

In our case, lets say our servers are in German timezone i.e. CET

-- With original settings
SET system:user.country;
+-------------------------+--+
|           set           |
+-------------------------+--+
| system:user.country=GB  |
+-------------------------+--+

-- Original settings
SET mapreduce.map.java.opts=-Duser.timezone=CET;
SET mapreduce.reduce.java.opts=-Duser.timezone=CET;

SELECT
	FROM_UNIXTIME(time_field, 'yyyy-MM-dd HH:mm:ss z') as date_z_from_string
	,COLLECT_SET(FROM_UNIXTIME(time_field, 'yyyy-MM-dd HH:mm:ss z')) as date_z_collect_set
FROM (SELECT CAST('1333047109' AS BIGINT) AS time_field) t
GROUP BY time_field
;

-- This is not the output we want:
+---------------------------+-------------------------------+--+
|    date_z_from_string     |       date_z_collect_set      |
+---------------------------+-------------------------------+--+
| 2012-03-29 20:51:49 CEST  | ["2012-03-29 20:51:49 CEST"]  |
+---------------------------+-------------------------------+--+

Fixing the configuration to convert it to UTC always

-- Set this hive configuration, then it automatically converts it to UTC timezone, there wont be any code change needed.
SET mapreduce.map.java.opts=-Duser.timezone=UTC;
SET mapreduce.reduce.java.opts=-Duser.timezone=UTC;

SELECT
	FROM_UNIXTIME(time_field,'yyyy-MM-dd HH:mm:ss z') as date_z_from_string
	,COLLECT_SET(FROM_UNIXTIME(time_field,'yyyy-MM-dd HH:mm:ss z')) as date_z_from_array
FROM (SELECT CAST('1333047109' AS BIGINT) AS time_field) l
GROUP BY time_field
;

-- Expected output:
+--------------------------+------------------------------+--+
|    date_z_from_string    |      date_z_collect_set      |
+--------------------------+------------------------------+--+
| 2012-03-29 18:51:49 UTC  | ["2012-03-29 18:51:49 UTC"]  |
+--------------------------+------------------------------+--+